Derive linear density expressions for FCC [100] and [111] directions in terms of the atomic radius R and (b) compute linear density values for these two directions for silver.

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Answer:

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In this exercise we want to calculate the linear density of a computer, in this way we find that:

A)[tex][100]=0.3536 atoms[/tex]
B)[tex][111]=0.204 atoms[/tex]

So calculating the diagonal of a square we have:

[tex]D(d)= 4R\\d^2=a^2+a^2\\d=a\sqrt 2\\a=2\sqrt 2R[/tex]

A)Now doing the calculation of the atoms along the bar [100]  we have:

[tex]AL= 1/2\sqrt2R\\=1/2\sqrt2\\=0,3536 atms[/tex]

B)Now doing the calculation of the atoms along the bar [111]  we have:

[tex]AL= 1/2\sqrt3R\\=1/2\sqrt2*\sqrt3\\=1/2\sqrt6\\=0.204 atoms[/tex]

See more about density at brainly.com/question/24650225