Answer:
Each would use 15 W power.
Together they would use 30 W.
Explanation:
For the 60 W bulb R = ΔV²/P= (120)²/60=14400/60= 240 OHMS
We can use Ohms Law to find the current
I =ΔV/R= 120/240= 0.5 Amperes
When they are placed in series the total resistance is about 480 ohms, so each bulb sees a current of 120/480 = 0.25 A.
Using the power equation to find the power of the bulbs in series
P= I²R= 0.25²* 240= 0.0625 *240= 15 W
Each would use 15 W power.
Together they would use 30 W.
Answer:15 watts
Explanation:
To get the current
Power P=iV
(Where P is power of bulb 60watts, i is current, and V is the voltage 120V
i=P/V
i = 60/120
i = 1/2A
But
V=iR where R is the resiance
Therefore R=V/i
=120÷1/2
=120×2
=240ohms
For series connection, each bulb draws the same current since,
Since the two bulbs are 60-watt bulbs, they will have the same resistance, therefore the voltage across each bulb is the same and equals halve of the applied voltage, 120/2 = 60 volts.
Taken the resistance 240 ohm is constant across the series, we can roughly estimate the current flow and calculate power dissipation in the series connection.
We have 120 V/(240 + 240 ) ohms = 1/4 A.
The power dissipated in each bulb is (1/4) × 60 = 15 watts.
