[tex]\text{Hey there!}[/tex]
[tex]\mathsf{The\ quadratic\ formula\ is: ax^2+bx+c=0}[/tex]
[tex]\mathsf{Use\ this\ formula\ to\ solve: x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}[/tex]
[tex]\mathsf{ax^2=x^2}[/tex]
[tex]\mathsf{bx=14x}[/tex]
[tex]\mathsf{c=17}[/tex]
[tex]\mathsf{0=96}[/tex]
[tex]\mathsf{x^2+14x+17=96}[/tex]
[tex]\text{Subtract by 96 on your sides}[/tex]
[tex]\mathsf{x^2+14x+17-96=96-96}[/tex]
[tex]\text{Cancel out: 96 - 96 because it gives you the result of 0}[/tex]
[tex]\text{Keep: 17 - 96 because it helps us solve for our equation. 17 - 96 = -79}[/tex]
[tex]\mathsf{x^2+14x-79=0}[/tex]
[tex]\mathsf{Use\ the\ 2^{nd}\ formula\ to\ solve}[/tex]
[tex]\mathsf{x=(-14)\pm\dfrac{(14)^2-4(1)(-79)}{2)(1)}}[/tex]
[tex]\mathsf{(14)^2-4(1)(-79)=196-4(1)(-79)\rightarrow512}[/tex]
[tex]\mathsf{2(1)=2}[/tex]
[tex]\mathsf{x=\dfrac{-14\pm\sqrt{512}}{2}}[/tex]
[tex]\mathsf{Solve\ that\ above\ and\ you\ have\ your\ result!}[/tex]
[tex]\boxed{\mathsf{Thus\ your\ answer\ is: x=-7+8\sqrt{2}\ or\ x = -7-8\sqrt{2}}}\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{LoveYourselfFirst:)}[/tex]
