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The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.

Determine the potential at x = 0. V
Determine the potential at x = 3.00 m. V
Determine the potential at x = 6.00 m.

Respuesta :

Answer:

[tex]V(0)=15.4\\V(3)=0.1\\V(6)=-15.2[/tex]

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, [tex]V=15.4-5.10x[/tex]

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

[tex]V=15.4-0=15.4[/tex]

Potential at x = 3:

[tex]V=15.4-5.10(3)=15.4-15.3=0.1[/tex]

Potential at x = 6:

[tex]V=15.4-5.10(6)=15.4-30.60=-15.2[/tex]

Therefore,

[tex]V(0)=15.4\\V(3)=0.1\\V(6)=-15.2[/tex]