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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:

PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5

Respuesta :

Answer:

The new partial pressures after equilibrium is reestablished for [tex]PCl_3[/tex]:

[tex]P_1'=6.798 Torr[/tex]

The new partial pressures after equilibrium is reestablished [tex]Cl_2[/tex]:

[tex]P_2'=26.398 Torr[/tex]

The new partial pressures after equilibrium is reestablished for [tex]PCl_5[/tex]:

[tex]P_3'=223.402 Torr[/tex]

Explanation:

[tex]PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g) [/tex]

At equilibrium before adding chlorine gas:

Partial pressure of the [tex]PCl_3=P_1=13.2 Torr[/tex]

Partial pressure of the [tex]Cl_2=P_2=13.2 Torr[/tex]

Partial pressure of the [tex]PCl_5=P_3=217.0 Torr[/tex]

The expression of an equilibrium constant is given by :

[tex]K_p=\frac{P_1}{P_1\times P_2}[/tex]

[tex]=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245[/tex]

At equilibrium after adding chlorine gas:

Partial pressure of the [tex]PCl_3=P_1'=13.2 Torr[/tex]

Partial pressure of the [tex]Cl_2=P_2'=?[/tex]

Partial pressure of the [tex]PCl_5=P_3'=217.0 Torr[/tex]

Total pressure of the system = P = 263.0 Torr

[tex]P=P_1'+P_2'+P_3'[/tex]

[tex]263.0Torr=13.2 Torr+P_2'+217.0 Torr[/tex]

[tex]P_2'=32.8 Torr[/tex]

[tex]PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g) [/tex]

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

[tex]K_p=\frac{P_3'}{P_1'\times P_2'}[/tex]

[tex]1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}[/tex]

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for [tex]PCl_3[/tex]:

[tex]P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr[/tex]

The new partial pressures after equilibrium is reestablished [tex]Cl_2[/tex]:

[tex]P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr[/tex]

The new partial pressures after equilibrium is reestablished for [tex]PCl_5[/tex]:

[tex]P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr[/tex]

equilibrium is a situation in which economic forces such as supply and demand are balanced and in the absence of external influences the values of economic variables will not change

The equilibrium constant depends on the following:-

  • Pressure
  • Volume

The formula used in the question is as follows:-

[tex]k_p = \frac{P_1}{P_1*P_2}[/tex], After putting the value, the equilibrium constant is as follows:-

[tex]k_p = \frac{217}{13.2*13.2}[/tex]

After solving it, the equilibrium constant is 1.245.

The pressure in different systems is as follows:-

Hence, the total pressure is:- [tex]P_1 + P_2+ P_3[/tex]

[tex]263 = 13.2 + P_2 + 217[/tex]

After solving it, the P2 is 32.8torr.

The equilibrium constant in the second case is:-

[tex]k_p = \frac{P_1^'}{P_1^' * P_2^'}[/tex]

After putting the value,

[tex]1.245= \frac{217+x}{(13.2-x )* (32.8-x)}[/tex]

After solving, the value of x is 6.402torr

Hence, the partial pressure [tex]PCL_3,\ CL2, \ PLC_5\[/tex] is 6.798, 26.398, and 223.402 respectively.

For more information, refer to the link;-

https://brainly.com/question/18222206

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