Answer:
Positively charged particle
Explanation:
¹⁰₆C → ¹⁰₅B + e⁺ + ve
Since there is a decrease in the atomic number, there has been nuclear transmutation and a proton has be broken into a neutron and positron with the release of neutrino which has zero charge and very small mass. This is a beta plus decay with the release of Positively charged particle
(a) positively charged
Let's take the scenario step by step
(i) Carbon-10 with 6 protons and 4 neutrons. i.e
¹⁰₆C
(ii) Undergoes a radioactive beta decay (β) decay to form Boron-10 with 5 protons and 5 neutrons ¹⁰₅B as follows;
¹⁰₆C => ¹⁰₅B + β -----------------------(i)
Remember that;
β decay can either be β- or β+
Where;
β - = ⁰₋₁ e⁻ (called electron and is negatively charged)
β + = ⁰₁ e⁺ (called positron and is positively charged)
Now, to balance the equation (i) above, β+ has to be used as follows;
¹⁰₆C => ¹⁰₅B + ⁰₁ e⁺
Therefore, the additional particle produced during this decay is ⁰₁ e⁺ (called positron and is positively charged)
