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18-02-2020
Chemistry

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Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt.

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18-02-2020

Answer:

The molality is 0.930 mol/kg

Explanation:

Molality = molarity ÷ density

Molarity of sucrose = 1.06 M = 1.06 mol/L

Density of sucrose = 1.14 g/mL = 1.14 g/mL × 1 kg/1000 g × 1 mL/ 0.001 L = 1.14 kg/L

Molality = 1.06 mol/L ÷ 1.14 kg/L = 0.930 mol/kg

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