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A proton (rest mass 1.67×10−27kg) is moving at 0.905 c. Find the momentum of the proton.Express your answer with the appropriate units.

Respuesta :

Answer:

  P= 4.52 x 10⁻¹⁹  kg.m/s

Explanation:

Given that

m = 1.67 x 10⁻²⁷ kg

V= 0.905 C

We know that

C= 3 x 10 ⁸ m/s

Therefore ,V= 0.905 x  3 x 10 ⁸ m/s

V= 2.71 x 10 ⁸ m/s

The linear momentum P is given as

P= m V

P= 1.67 x 10⁻²⁷ x 2.71 x 10 ⁸  kg.m/s

P= 4.52 x 10⁻¹⁹  kg.m/s

Therefore the answer will be  4.52 x 10⁻¹⁹  kg.m/s.

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