Answer:
Option 2nd is correct
x equals five plus or minus the square root of negative five squared minus four times two times eighteen, all divided by two times two
Step-by-step explanation:
Given the equation:
[tex]y = 2x^2-5x+18[/tex]
Use the quadratic formula:
A quadratic equation [tex]y = ax^2+bx+c[/tex].............[1], then the solution is given by:
[tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
On comparing given equation with [1]
a = 2 , b = -5 and c = 18
then;
[tex]x = \frac{-(-5) \pm \sqrt{(-5)^2-4(2)(18)}}{2(2)}[/tex]
⇒[tex]x = \frac{5 \pm \sqrt{(-5)^2-4(2)(18)}}{2(2)}[/tex]
Therefore, the correct application of the quadratic formula is,
x equals five plus or minus the square root of negative five squared minus four times two times eighteen, all divided by two times two
