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What is the period of a satellite in a circular orbit just above the surface of the Moon? The Moon’s mass is 7.36 × 1022 kilograms and its radius is
1.738 × 106 meters.

Respuesta :

metchelle
The period of a satellite in a circular orbit can be obtained by using the formula below:

P = √(4π²r³/GM)

Where: constant GM of the Moon (gravity * mass) = 4.903x10^12 m³/s²

Substituting and simplifying:

P = 2.838x10^(-6) * √(1.738x10^6)³
P = 6502 seconds, or 108.37 minutes
hannahcalef

It's C. 6.50 x 10^3 seconds for plato :)

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