For this case we have the following quadratic function:
[tex] 0 = 2x^2 + 3x - 8[/tex]
Using the method of the resolver we have:
[tex]x = \frac{-b +/- \sqrt{b^2-4ac} }{2a} [/tex]
Substituting values:
[tex]x = \frac{-3 +/- \sqrt{3^2-4(2)(-8)} }{2(2)} [/tex]
Rewriting we have:
[tex]x = \frac{-3 +/- \sqrt{9+64} }{4} [/tex]
[tex]x = \frac{-3 +/- \sqrt{73} }{4} [/tex]
Doing the calculations we have the results are:
[tex]x1 = 1,386
x2 = -2,886[/tex]
Rounding the positive solution to the hundredth hundredth:
[tex]x1 = 1.39
[/tex]
Answer:
The positive solution to the quadratic equation is:
[tex]x = 1.39[/tex]
