see the attached figure to better understand the problem
we know that
Applying the Pythagorean Theorem
[tex] c^{2}= a^{2} +b^{2} [/tex] ------> equation [tex] 1 [/tex]
Area of the square [tex] 1 [/tex]
[tex] A1=a^{2} unit^{2} [/tex]
Area of the square [tex] 2 [/tex]
[tex] A2=b^{2} unit^{2} [/tex]
Area of the square [tex] 3 [/tex]
[tex] A3=c^{2} unit^{2} [/tex]
Substitute the values of A1, A2 and A3 in the equation [tex] 1 [/tex]
[tex] A3=A1+A2 [/tex]
therefore
the answer is the option
C.(Area of 1) + (Area of 2) = (Area of 3).
