In a group of 55 people, 33 are coffee drinkers and 12 are tea drinkers. Assuming that no one in this group drinks both tea and coffee, what is the probability that a person picked at random from the group does not drink tea or coffee?

Respuesta :

Since the whole set is composed of a total of 55 people, with 45 people being drinks of either coffer or tea, then the remaining people not included in the 45 would be the non-drinkers. So 55-45, meaning there are 10 people who drink neither tea nor coffee. To obtain the probability:

10/55 = 2/11 = 0.182

Therefore, the probability of a person being picked at random does not drink either coffee or tea is 0.182.

The probability of a person being picked at random who does not drink either coffee or tea is 0.182.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

In a group of 55 people, 33 are coffee drinkers and 12 are tea drinkers.

Assuming that no one in this group drinks both tea and coffee

The total of 55 people, with 45 people being drinks of either coffee or tea, then the remaining people not included in the 45 will be the non-drinkers.

So 55-45,

There are 10 people who drink neither tea nor coffee.

The probability that a person picked at random from the group does not drink tea or coffee

= 10/55

= 2/11

= 0.182

Therefore, the probability of a person being picked at random who does not drink either coffee or tea is 0.182.

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