kimsouthach
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A radio telescope has a parabolic surface as shown below. . . A parabola opening up with vertex at the origin is graphed on the coordinate plane. The height of the parabola from top to bottom is 1 meter and its width from left to right is 20 meters. . . If the telescope is 1 m deep and 20 m wide, how far is the focus from the vertex?.

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taskmasters
There are several information's that are already given in the question. Based on those given information's, one can say that the origin of the parabola is opening up with the vertex of the parabola. We already know that the formula for a parabola with vertex at the origin is x^2 = 4py, where "p" is the focus. Now putting the dimensions given in the question in the formula, we get 0.25 as the correct result. I hope the answer has come to your help.

azikennamdi

The distance of the focus from the vertex 25m. See the explanation below.

What is a parabola?

A parabola is a symmetrical open plane curve created when a cone and a plane that runs perpendicular to its side collide.

How is the answer to the question derived?

Recall that the expression for determining the dimensions of a parabola is:

x² =2py

Pont given are: (10,1) (-10, 1)

Thus, 100 = 2p

⇒ P = 50

It is to be noted that the equation of the directrix is

y = -(p/2)

= -25

Hence the directrix or distance of the  focus from the vertex 25.m

Learn more about parabolas at;
https://brainly.com/question/4148030
#SPJ5

Ver imagen azikennamdi

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