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The engine of a 1520-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road. Is your answer realistic?

Respuesta :

Answer:

t=15.68 s

Explanation:

Given that

m = 1520 kg

P =75 KW

We know that

Power  ,P = F .v

F=force

v=velocity

v= 100 km/h

[tex]v=\dfrac{1000}{3600}\times 100\ m/s[/tex]

v=27.77 m/s

75 x 1000  = F x 27.77

[tex]F= \dfrac{75000}{27.77}\ N[/tex]

F= 2700.75 N

F= m a

m=mass

a=acceleration

2700.75 = 1520 x a

 a=1.77 m/s²

time t given as

v= u + a t

27.77 = 0 + 1.77 x t

t=15.68 s

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