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Three 1.0 kg masses are located at the corners of a vertically standing equilateral triangles with sides 0.80 m long. (a) what is the mutual gravitational potential energy?

Respuesta :

Answer:

gravitational potential energy = -2.50 × [tex]10^{-10}[/tex]   J

Explanation:

given data

mass m = 1 kg

length l = 0.80 m

solution

we get here mutual gravitational potential energy that is express as

As Potential energy between two masses = [tex]\frac{-Gm^2}{l}[/tex]   .........1

here is 3 pair of mass so

gravitational potential energy =  [tex]\frac{-3*6.67*10^{-11}*1^2}{0.80}[/tex]

gravitational potential energy = -2.50 × [tex]10^{-10}[/tex]    J

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