Answer:
4.7953 x 10⁻¹⁹ m³
Step-by-step explanation:
Length of the Escherichia coli cell (L) = 2.65 x 10⁻⁶ m
Diameter of the Escherichia coli cell (D) = 0.480 x 10⁻⁶ m
The volume of cylinder in given by:
[tex]V= \frac{\pi D^2}{4}*L \\V= \frac{\pi (0.480*10^{-6})^2}{4}*2.65*10^{-6}\\V= 4.7953*10^{-19} m^3[/tex]
The volume of an E. coli cell is 4.7953 x 10⁻¹⁹ m³.
