Respuesta :
The specific gravity is the ratio of the substances density to that of water at 4 degrees Celsius. With this, it is conclusive that the density of iron is 7.87 g/cm³. The volume occupied by the iron is the quotient when mass is divided by density,
V = m / D = (7 g) / (7.87 g/cm³) = 0.89 cm³
Therefore, 7 grams of iron occupies approximately 0.89 cm³.
V = m / D = (7 g) / (7.87 g/cm³) = 0.89 cm³
Therefore, 7 grams of iron occupies approximately 0.89 cm³.
Let us first write down all the information's that are already given.
Specific gravity of iron = 7.87
Density of water at 4 degree centigrade = 1.00 g/cm^3
Mass of iron that is given in the question = 7.00 g
Now
Specific gravity of iron = Density of iron/density of water
So
Density of iron = specific gravity of iron * density of water
= 7.87 * 1 g/cm^3
= 7.87 g/cm^3
We also know
Volume = Mass/ Density
So
Volume of iron = 7/7.87 cm^3
= 0.89 cm^3
So the volume of 8.00 gm of iron is 0.89 cm^3. i hope the answer comes to your help.
Specific gravity of iron = 7.87
Density of water at 4 degree centigrade = 1.00 g/cm^3
Mass of iron that is given in the question = 7.00 g
Now
Specific gravity of iron = Density of iron/density of water
So
Density of iron = specific gravity of iron * density of water
= 7.87 * 1 g/cm^3
= 7.87 g/cm^3
We also know
Volume = Mass/ Density
So
Volume of iron = 7/7.87 cm^3
= 0.89 cm^3
So the volume of 8.00 gm of iron is 0.89 cm^3. i hope the answer comes to your help.