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What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, starting with an initial velocity of 3.4 m/s

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Answer:

[tex]v_f=41.65\frac{m}{s}[/tex]

Explanation:

The final velocity is given by the following kinematic equation:

[tex]v_f=v_0+at[/tex]

Here, [tex]v_0[/tex] is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

[tex]7.5min*\frac{60s}{1min}=450s[/tex]

Now, we calculate the final velocity:

[tex]v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}[/tex]

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