Respuesta :
To determine the maxima and minima of the polynomial, differentiate the given based on x and equate to 0.
C(x) = 400x - 0.2x²
dC(x) / dt = 400 - 0.4 x = 0
The value of x is 1000. This is the value of the maxima. As the value of C(x) continously becomes lesser as the value of x is set higher, the minima is not identified. Substitute x to the original equation,
C(x) = (400)(1000) - 0.2(1000²) = $ 200,000
Thus, the answer is letter B.
C(x) = 400x - 0.2x²
dC(x) / dt = 400 - 0.4 x = 0
The value of x is 1000. This is the value of the maxima. As the value of C(x) continously becomes lesser as the value of x is set higher, the minima is not identified. Substitute x to the original equation,
C(x) = (400)(1000) - 0.2(1000²) = $ 200,000
Thus, the answer is letter B.
The correct answer to this question is letter "B. One thousand units have the maximum cost of $200,000."
C(x) = 400 - 0.2x^2
0 = 400 - 0.2^2
0.2x^2 = 400
x^2 = 2000
dC(x) / dt = 400 - 0.4 x = 0
C(x) = (400)(1000) - 0.2(1000²) = $ 200,000
C(x) = 400 - 0.2x^2
0 = 400 - 0.2^2
0.2x^2 = 400
x^2 = 2000
dC(x) / dt = 400 - 0.4 x = 0
C(x) = (400)(1000) - 0.2(1000²) = $ 200,000