The area of a rectangle is obtained through the equation,
A = L x W
The width of the yard is 4 ft less than the length and may be expressed as L - 4. Length may be solved through the following steps,
A = (L)(L-4) ; 96 = L(L - 4) ; L = 12 ft
The length and width are 12 ft and 8 ft, respectively. Perimeter may be solved through the equation,
P = 2 x (L + W)
Substituting the values of L and W
P = 2 x ( 12 ft + 8 ft) = 40 ft
Therefore, the perimeter of the yard is 40 ft.
