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Two Masses, a Pulley, and an Inclined Plane. . Block 1, of mass m1 = 0.700kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2, as shown. For an angle of θ = 30.0∘ and a coefficient of kinetic friction between block 2 and the plane of μ = 0.200, an acceleration of magnitude a = 0.200m/s2 is observed for block 2.. . find the mass of block 2, m2:

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Hagrid
The answer to this is 1 kg.
You use this equation:
m2 = m1 (g - a) / [a + g u cos θ + g sin θ]

You plug in the given values:
m2 = 0.7 (9.81 - 0.2) / [0.2 + 9.81(0.20) cos 30 + 9.81 sin 30)

The result is
m2 = 1 kg
abidemiokin

The mass of the block m2 is 0.495kg

In order to get the mass of block 2 according to the given equation, we will use the formula below:

[tex]m_2=\frac{m_1(g-a)}{a+g\mu cos\theta + gsin\theta}[/tex]

Given the following parameters

m1 - 0.7kg

g = 9.8m/s²

a = 0.2m/s²

[tex]\mu=0.2[/tex]

[tex]\theta = 30^0[/tex]

Substitute the given parameters into the formula as shown:

[tex]m_2=\frac{0.7(9.8-0.2)}{0.2+9.8\mu cos30 + 9.8sin30}\\m_2=\frac{0.7\times9.6}{0.2+ 8.4870+ 4.9}\\m_2=\frac{6.72}{13.587}\\m_2=0.495kg[/tex]

Hence the mass of the block m2 is 0.495kg

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