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In a random sample of 70 people, it was found that 44 of them were fans of the New York Yankees. What is the margin of error for the true proportion of all individuals who are fans of the New York Yankees?. A. 0.0088 . B. 0.058. C. 0.063. D. 0.116. E. 0.173

Respuesta :

meerkat18
The general formula for the margin of error would be:

z * √[p (1-p) ÷ n]

where:
z = values for selected confidence level
p = sample proportion
n = sample size

Since the confidence level is not given, we can only solve for the 
√[p (1-p) ÷ n]  part.

p = 44/70
n = 70

√[44/70 (1 - (44/70) ÷ 70]

√[0.6286 (0.3714)] ÷ 70

√0.2335 ÷ 70

√0.0033357 = 0.05775 or 0.058 Choice B.

The margin of error for the true proportion of all individuals who are fans of the New York Yankees is; B. 0.058

How to find the margin of error?

The formula to calculate the margin of error  for the true proportion is;

M = √[p(1 - p)/n]

where:

p = sample proportion

n = sample size

We are given;

p = 44/70 = 0.6286

n = 70

Thus;

M = √[0.6286(1 - 0.6286)/70]

M = √0.003335172

M ≈ 0.058

Read more about Margin of Error at; https://brainly.com/question/10218601

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