If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis,and rotated 180°, where would point A' lie?. . Trapezoid formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at 0, 1.. . (1,-1). . (-4,1). . (1,1). . (-4,-1).

just imagine flipping it across the y-axis like a mirror, then the same below the x-axis....then spin it so that the trapezoid is located with its shorter base on the north side.

180 degrees is making it upside down pretty much them just follow the 'A' point on the trapezoid.

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DelcieRiveria DelcieRiveria · Answer 2 · 2019-03-11T12:26:43+01:00

Answer:

The correct option is 2. The coordinates of A' are (-4,1).

Step-by-step explanation:

The vertices of trapezoid ABCD are A(-4,1), B(-3,2), C(-1,2) and D(0,1).

If trapezoid ABCD was reflected over the y-axis,

[tex](x,y)\rightarrow (-x,y)[/tex]

[tex](-4,1)\rightarrow (4,1)[/tex]

After that ABCD was reflected over the x-axis,

[tex](x,y)\rightarrow (x,-y)[/tex]

[tex](4,1)\rightarrow (4,-1)[/tex]

At the end ABCD rotated 180°.

[tex](x,y)\rightarrow (-x,-y)[/tex]

[tex](4,-1)\rightarrow (-4,1)[/tex]

The relation between image and preimage is

[tex]P(x,y)\rightarrow P'(x,y)[/tex]

[tex]A(-4,1)\rightarrow A'(-4,1)[/tex]

Therefore the correct option is 2. The coordinates of A' are (-4,1).