The balanced molecular equation is [tex]\boxed{{\text{Ca}}{{\left( {{\text{OH}}} \right)}_2}\left( {aq} \right) + {\text{2HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) \to {\text{Ca}}{{\left( {{\text{N}}{{\text{O}}_3}} \right)}_2}\left( {aq} \right) + 2{{\text{H}}_2}{\text{O}}\left( l \right)}[/tex]
Further Explanation:
The three types of equations that are used to represent the chemical reaction are as follows:
1. Molecular equation
2. Total ionic equation
3. Net ionic equation
The reactants and products remain in undissociated form in the molecular equation. In the case of total ionic equation, all the ions that are dissociated and present in the reaction mixture are represented while in case of the overall or net ionic equation only the useful ions that participate in the reaction are represented.
The steps to write the molecular equation are as follows:
Step 1: Write the molecular equation for the reaction with the phases in the bracket.
In the reaction, [tex]{\text{Ca}}{\left( {{\text{OH}}}\right)_2}[/tex] reacts with [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex] to form [tex]{\text{Ca}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}[/tex] and [tex]{{\text{H}}_2}{\text{O}}[/tex]. The unbalanced chemical equation is as follows:
[tex]{\text{Ca}}{\left( {{\text{OH}}} \right)_2}\left( {aq} \right) + {\text{HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) \to {\text{Ca}}{\left( {{\text{N}}{{\text{O}}_3}} \right)_2}\left( {aq} \right) + {{\text{H}}_2}{\text{O}}\left( l \right)[/tex]
Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.
• On reactant side,
Number of calcium atom is 1.
Number of hydrogen atoms is 3.
Number of oxygen atoms is 5.
Number of nitrogen atom is 1.
• On the product side,
Number of calcium atom is 1.
Number of hydrogen atoms is 2.
Number of oxygen atoms is 7.
Number of nitrogen atoms is 2.
Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. Calcium atoms are balanced on both sides. To balance the number of nitrogen atoms multiply [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex] by 2. Now the reaction is,
[tex]{\text{Ca}}{\left( {{\text{OH}}} \right)_2}\left( {aq} \right) + \boxed2{\text{ HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) \to {\text{Ca}}{\left( {{\text{N}}{{\text{O}}_3}} \right)_2}\left( {aq} \right) + {{\text{H}}_2}{\text{O}}\left( l \right)[/tex]
Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. There is no carbon atom in the reaction. To balance the number of hydrogen and oxygen atoms, multiply [tex]{{\text{H}}_2}{\text{O}}[/tex] by 2. Now the reaction is,
[tex]{\text{Ca}}{\left( {{\text{OH}}} \right)_2}\left( {aq} \right) + \boxed2{\text{ HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) \to {\text{Ca}}{\left( {{\text{N}}{{\text{O}}_3}} \right)_2}\left( {aq} \right) + \boxed2{\text{ }}{{\text{H}}_2}{\text{O}}\left( l \right)[/tex]
Step 5: Finally, we check the number of atoms of each element on both sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:
[tex]{\text{Ca}}{\left( {{\text{OH}}} \right)_2}\left( {aq} \right) + {\text{2HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) \to {\text{Ca}}{\left( {{\text{N}}{{\text{O}}_3}} \right)_2}\left( {aq} \right) + 2{{\text{H}}_2}{\text{O}}\left( l \right)[/tex]
Learn more:
1. Balanced chemical equation: https://brainly.com/question/1405182
2. Identify the precipitate in the reaction: https://brainly.com/question/8896163
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Chemical reaction and equation
Keywords: Balancing, Ca(OH)2, HNO3, Ca(NO3)2, H2O, calcium, hydrogen, oxygen, nitrogen, 1, 2, 3, 5, 7.
