Respuesta :
The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.
Explanation:
An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.
So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as [tex]c a^{+}[/tex] ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to [tex]F^{-}[/tex] ions. This process of acceptance of electrons is termed as reduction.
When calcium reacts with fluorine to produce calcium fluoride, calcium is oxidized and fluorine is reduced.
From the question,
We are to explain how oxidation and reduction take place in the reaction between calcium and fluorine.
First, we will define the terms oxidation and reduction
Oxidation
Oxidation can be defined as gain of oxygen. It can also be defined as an increase in oxidation state
Reduction
Reduction can be defines as loss of oxygen. It can also be defines as a decrease in oxidation state.
Now, we will write a chemical equation for the reaction.
The chemical equation for the reaction is
Ca + F₂ → CaF₂
The oxidation number of calcium increased from 0 to +2. This means calcium was oxidized .
The oxidation number of Fluorine decreased from 0 to -2. This means fluorine was reduced.
Hence, when calcium reacts with fluorine to produce calcium fluoride, calcium is oxidized and fluorine is reduced.
Learn more on Oxidation and Reduction here: https://brainly.com/question/12913997
