JKLM is a parallelogram.
Find m

Good evening ,
Answer:
Step-by-step explanation:
the sum of measures of angles of a parallelogram = 360°
2[(2z-3)+(5z-6)] = 360
⇔ 2[7z - 9] = 360 ⇔ 14z - 18 = 360 ⇔ 14z = 378 ⇔ z = 27
m∠L = 2z - 3 = 2(27) - 3 = 54 - 3 = 51.
:)
Answer:
Step-by-step explanation:
In any parallelogram, the sum of the angle measures on one side is 180°.
Therefore we have the equation:
[tex](2z-3)^o+(5z-6)^o=180^o[/tex]
Let's skip the degree marks and parentheses
[tex]2z-3+5z-6=180[/tex] combine like terms
[tex](2z+5z)+(-3-6)=180[/tex]
[tex]7z-9=180[/tex] add 9 to both sides
[tex]7z-9+9=180+9[/tex]
[tex]7z=189[/tex] divide both sides by 7
[tex]\dfrac{7z}{7}=\dfrac{189}{7}[/tex]
[tex]z=27[/tex]
Put the value of z to the expression m∡L = (2z - 3)°:
[tex]m\angle L=(2\cdot27-3)^o=(54-3)^o=51^o[/tex]