Answer:
we should know that :
sin ( a + b ) = sin a * cos b + sin b cos a
For the given equation :
sin (π + q) = sin π * cos q + sin q * cos π
sin π = zero and cos π = -1
∴ sin (π + q) = 0 * cos q + sin q * (-1) = - sin q
Another solution:
The angle (π + q) lies in the third quarter ⇒ (1)
(π + q) and (-q) are supplementary angles ⇒ (2)
From (1) and (2)
sin(π + q) = -sin q
Answer:
sinπcosq + cosπsinq
Step-by-step explanation:
This was the answer on edg
i'm just as clueless so I'm trying to help from my mistakes
