Respuesta :
Answer:
[Fe(NO₃)₃] = 0.90 M
Explanation:
Molarity = Mol/L
Total volume of solution: 31.65 mL + 44.96 mL = 76.61 mL
Let's determine the moles of salt ([M] . volume)
0.03165 L . 1.07M = 0.0338 moles
0.04496L . 0.79M = 0.0355 moles
Total moles Fe(NO₃)₃ = 0.0338 + 0.0355 = 0.0693 moles
Volume of solution = 76.61 mL = 0.07661 L
0.0693 mol / 0.07661 L = 0.90 mol/L
Answer:
The molar concentration of the final solution is 0.9057 M
Explanation:
Step 1: Data given
Volume of a 1.07 M Fe(NO3)3 solution = 31.65 mL = 0.03165 L
Volume of a 0.79 M Fe(NO3)3 solution = 44.96 mL = 0.04496 L
Step 2: Calculate moles of 1.07 M Fe(NO3)3 solution
Moles = molarity * volume
Moles = 1.07 M * 0.03165 L
Moles = 0.0338655 moles
Step 3: Calculate moles of 0.79 M Fe(NO3)3 solution
Moles = 0.79 M * 0.04496 L
Moles = 0.0355184 moles
Step 4: Calculate total moles
Total moles = 0.0339 + 0.0355
Total moles = 0.0693839 moles
Step 5: Calculate total volume
Total volume = 31.65 mL + 44.96 mL
Total volume = 76.61 mL = 0.07661 L
Step 6: Calculate molar concentration of the final solution
Concentration = moles / volume
Concentration = 0.0693839 moles / 0.07661 L
Concentration = 0.9057 M
The molar concentration of the final solution is 0.9057 M