Answer:
[tex]F'=2F[/tex]
Explanation:
The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:
[tex]F=\frac{kq_1q_2}{d^2}[/tex]
In this case, we have [tex]q_1'=2q_1[/tex]:
[tex]F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F[/tex]
