Answer:
Explanation:
Given
Velocity of ship relative to water is [tex]8.5 \m/s[/tex]
[tex]V_{sw}=V_{s}-V_{w}=8.5\hat{j}----1[/tex]
Velocity of water with respect to earth
[tex]V_{we}=V_{w}-V{e}=1.5(\cos (40)\hat{i}+\sin (40)\hat{j})----2[/tex]
adding 1 and 2
[tex]V_{s}-V_{e}=1.5\cos (40)\hat{i}+8.5\hat{j}+1.5\sin (40)\hat{j}[/tex]
[tex]V_{s}-V_{e}=1.5\cos (40)\hat{i}+9.46\hat{j}[/tex]
[tex]|V_{se}|=\sqrt{(1.149)^2+(9.46)^2}[/tex]
[tex]|V_{se}|=\sqrt{90.8118}[/tex]
[tex]|V_{se}|=9.53\ m/s[/tex]
