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What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the point (–12, 10)?
a.y = x – 6
b.y = x + 6
c.y = x + 26
d.y = x + 10

Respuesta :

anthony1669
y= 3/4x - 2   (-2,10)= (x1,y1)
The slope is -4/3 of the perpendicular line:
Then:
y-y1=m(x-x1)
y-10=(-4/3)(x+2)
y=-(4/3)x -8/3 +10
y= -(4/3)x +22/3 (That's the answer)

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