someone help me with quadratics? will give points

The answer is Option 1: [tex]\frac{1\±i\sqrt{31}}{2}[/tex]
Step-by-step explanation:
Given equation is;
x²-x+8=0
Here,
a=1 , b= -1 , c=8
Quadratic formula is;
[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]
Putting values in equation;
[tex]x=\frac{-(-1)\±\sqrt{(-1)^2-4(1)(8)}}{2(1)}\\\\x=\frac{1\±\sqrt{1-32}}{2}\\\\x=\frac{1\±\sqrt-31}{2}\\\\x=\frac{1\±i\sqrt{31}}{2}[/tex]
The answer is Option 1: [tex]\frac{1\±i\sqrt{31}}{2}[/tex]
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