To answer the question above, determine the distance between the points which are the vertices of the triangle.
1. Between (-4,1) and (1,1) ; d1 = sqrt ((1-1)² + (1--4)²) = 5
2. Between (-4,1) and (1,-11) ; d2 = sqrt ((-11-1)² +(1--4)²) = 13
3. Between (1,1) and (1,-11) ; d3 = sqrt ((-11-1)² + (1-1)²) = 12
The perimeter is the sum of the three distances. Thus, the perimeter of the triangle is 30. The answer is letter A.
