Answer:
L = 0.44 [m]
Explanation:
Here we can use the Lorentz transformation related to length to solve it:
[tex]L=L_{0}\sqrt{1-\beta^{2}} [/tex]
Where:
L₀ is the length of the moving reference frame (penguin #1)
L is the length of the fixed reference frame (penguin #2)
β is the ratio between v and c
We know that v = 0.9c so we can find β.
[tex]\beta = \frac{0.9c}{c}=0.9[/tex]
[tex]L=1 [m]\sqrt {1-0.9^{2}} = 0.44 [m] [/tex]
Therefore, the length of the meter stick of #1 observed by #2 is 0.44 m.
I hope it helps you!
