Respuesta :
Answer:
Explanation:
position of centre of mass of door from surface of water
= 10 + 1.1 / 2
= 10.55 m
Pressure on centre of mass
atmospheric pressure + pressure due to water column
10 ⁵ + hdg
= 10⁵ + 10.55 x 1000 x 9.8
= 2.0339 x 10⁵ Pa
the net force acting on the door (normal to its surface)
= pressure at the centre x area of the door
= .9 x 1.1 x 2.0339 x 10⁵
= 2.01356 x 10⁵ N
pressure centre will be at 10.55 m below the surface.
When the car is filled with air or it is filled with water , in both the cases pressure centre will lie at the centre of the car .
The net force acting on the door (normal to its surface) and the location of the pressure should be [tex]2.01356 \times 10^5 N[/tex]
Calculation of net force & pressure location:
The position of center of mass of door from the surface of water should be
[tex]= 10 + 1.1 \div 2[/tex]
= 10.55 m
Now
Pressure on center of mass
= atmospheric pressure + pressure due to water column
[tex]= 10^5 + 10.55 \times 1000 \times 9.8\\\\= 2.0339 \times 10^5 Pa[/tex]
Now
the net force acting on the door (normal to its surface)
[tex]= .9 \times 1.1 \times 2.0339 \times 10^5\\\\= 2.01356 \times 10^5 N[/tex]
So,
pressure centre will be at 10.55 m below the surface.
Therefore,
When the car is filled with air or it is filled with water , in both the cases pressure center should be lie at the centre of the car .
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