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For a fiber-reinforced composite, the efficiency of reinforcement η is dependent on fiber length l according to where x represents the length of the fiber at each end that does not contribute to the load transfer. What length is required for a 0.62 efficiency of reinforcement, assuming that x is 0.61 mm?

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whitneytr12

Answer:

l = 3.21 mm

Explanation:

The efficiency of a fiber-reinforced is the following:

[tex] \eta = \frac{l - 2x}{l} [/tex]

Where:

η: is the efficiency

l: is the fiber length

x: is the length of the fiber at each end that doesn't contribute to the load transfer

So the length required for a 0.62 efficiency of reinforcement is:

[tex] l = \frac{2x}{1- \eta} = \frac{2 \cdot 0.61 mm}{1- 0.62} = 3.21 mm [/tex]

I hope it helps you!  

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