Respuesta :
Answer:
Reject the null hypothesis. There is sufficient evidence to prove that the mean life is different from 7463 hours.
95% confidence interval also supports this result.
Step-by-step explanation:
Let mu be the population mean life of a large shipment of CFLs.
The hypotheses are:
[tex]H_{0}[/tex]: mu=7463 hours
[tex]H_{a}[/tex]: mu≠7463 hours
Test statistic can be calculated using the equation:
z=[tex]\frac{X-M}{\frac{s}{\sqrt{N} } }[/tex] where
- X is the sample mean life of CFLs (7163 hours)
- M is the mean life assumed under null hypothesis. (7463 hours)
- s is the population standard deviation (1080 hours)
- N is the sample size (81)
Then z=[tex]\frac{7163-7463}{\frac{1080}{\sqrt{81} } }[/tex] = -2.5
p-value is 0.0124, critical values at 0.05 significance are ±1.96
At the 0.05 level of significance, the the result is significant because 0.0124<0.05. There is significant evidence that mean life of light bulbs is different than 7463 hours.
95% Confidence Interval can be calculated using M±ME where
- M is the sample mean life of a large shipment of CFLs (7163 hours)
- ME is the margin of error from the mean
margin of error (ME) from the mean can be calculated using the formula
ME=[tex]\frac{z*s}{\sqrt{N} }[/tex] where
- z is the corresponding statistic in the 95% confidence level (1.96)
- s is the standard deviation of the sample (1080 hours)
- N is the sample size (81)
Then ME=[tex]\frac{1.96*1080}{\sqrt{81} }[/tex] =235.2
Thus 95% confidence interval estimate of the population mean life of the light bulbs is 7163±235.2 hours. That is between 6927.8 and 7398.2 hours.