Answer:
Step-by-step explanation:
Given
mean [tex]\mu =12.9 Pounds[/tex]
Standard deviation [tex]\sigma =1\ Pound[/tex]
[tex]P(x<11)=P\left ( \frac{x-\mu }{\sigma }< \frac{11-12.9}{1}\right )[/tex]
[tex]P(x<11)=P\left ( z< -1.9\right )[/tex]
From z table
[tex]P(x<11)=0.0289\approx 0.029[/tex]