Answer:
The answer to your question is 2.1
Explanation:
Data
Molarity = 1 l
mass = 120 g of NaCl
moles = ?
Formula
[tex]Molarity = \frac{number of moles}{Volume}[/tex]
Process
1.- Calculate the number of moles of NaCl
Molecular weight NaCl = 23 + 35.5 = 58.5 g
2.- Calculate the number of moles using proportions
58.5 g of NaCl --------------- 1 mol
120.0 g of NaCl --------------- x
x = ( 120 x 1) / 58.5
x = 2.1 moles
3.- Calculate Molarity
Substitution
[tex]Molarity = \frac{2.1}{1}[/tex]
Simplification and result
Molarity = 2.1
Answer:
2.05 M
Explanation:
Molarity is defined as number of moles of solute in 1 L of solution.
Molarity = [tex]\frac{Number\ of\ moles\ of\ solute}{Volume\ of\ solution\ in\ L}[/tex]
Here we have 120 g of NaCl in 1 liter of solution.
Molar mass of NaCl = 58.5 g
Number of moles of NaCl = [tex]\frac{Given\ mass\ of\ solute}{Molar\ mass\ of\ solute}[/tex] = [tex]\frac{120}{58.5}=2.05\ moles[/tex]
Volume of solution = 1 L
Molarity = [tex]\frac{Number\ of\ moles\ of\ solute}{Volume\ of\ solution\ in\ L}=\frac{2.05}{1}=2.05\ moles\ per\ litre[/tex]
