A scientist measured the speed of light. His values are in​ km/sec and have​ 299,000 subtracted from them. He reported the results of 25 trials with a mean of 756.22 and a standard deviation of 100.89. ​

(a) Find a 90​% confidence interval for the true speed of light from these statistics.
(​b) State in words what this interval means. Keep in mind that the speed of light is a physical constant​ that, as far as we​ know, has a value that is true throughout the universe.
(​c) What assumptions must you make in order to use your​ method?

Respuesta :

Answer:

a) The 90% confidence interval would be given by (721.716;790.724)  

b) We are 90% confident that the true mean for the true speed of light is between (721.716;790.724)  

c) We assume the following conditions:

  1. Randomization
  2. Independence
  3. Deviation unknown [tex]\sigma[/tex]

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

[tex]\bar X=756.22[/tex] represent the sample mean  

[tex]\mu[/tex] population mean (variable of interest)  

[tex]s=100.89[/tex] represent the sample standard deviation  

n=25 represent the sample size  

90% confidence interval  

The confidence interval for the mean is given by the following formula:  

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)  

The degrees of freedom are given by:

[tex]df=n-1=25-1=24[/tex]

Since the Confidence is 0.90 or 90%, the value of [tex]\alpha=0.1[/tex] and [tex]\alpha/2 =0.05[/tex], and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,24)".And we see that [tex]t_{\alpha/2}=1.71[/tex]  

Now we have everything in order to replace into formula (1):  

[tex]756.22-1.71\frac{100.89}{\sqrt{25}}=721.716[/tex]  

[tex]756.22+1.71\frac{100.89}{\sqrt{25}}=790.724[/tex]  

So on this case the 90% confidence interval would be given by (721.716;790.724)  

Part b

We are 90% confident that the true mean for the true speed of light is between (721.716;790.724)  

Part c

We assume the following conditions:

  1. Randomization
  2. Independence
  3. Deviation unknown [tex]\sigma[/tex]