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What is stored in alpha after the following code executes?
int[] alpha = new int[5];int j;for (j = 0; j < 5; j++){alpha[j] = 2 * j;if (j % 2 == 1)alpha[j - 1] = alpha[j] + j;}1. alpha = {0, 2, 4, 6, 8}
2. alpha = {0, 2, 9, 6, 8}
3. alpha = {3, 2, 9, 6, 8}
4. alpha = {0, 3, 4, 7, 8}

Respuesta :

Answer:

3. alpha = {3, 2, 9, 6, 8}

Explanation:

Initially, we have that alpha[j] = 2*j;

j goes from 0 to 4.

So

alpha[0] = 0;

alpha[1] = 2;

alpha[2] = 4;

alpha[3] = 6;

alpha[4] = 8;

If (j%2 == 1), which happens when j = 1 and j = 3, alpha[j-1] = alpha[j]+j;

So

j = 1

alpha[1-1] = alpha[1]+1 = 2+1 = 3

So alpha[0] = 3

j = 3

alpha[3-1] = alpha[3]+3 = 6+3 = 9

So alpha[2] = 9

The correct answer is:

3. alpha = {3, 2, 9, 6, 8}

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