Respuesta :
Answer: 0.100 m [tex]K_2SO_4[/tex]
Explanation:
Elevation in boiling point is given by:
[tex]\Delta T_b=i\times K_b\times m[/tex]
[tex]\Delta T_b=T_b-T_b^0[/tex] = Elevation in boiling point
i= vant hoff factor
[tex]K_b[/tex] = boiling point constant
m= molality
1. For 0.100 m [tex]K_2SO_{4}[/tex]
[tex]K_2SO_4\rightarrow 2K^{+}+SO_4^{2-}[/tex]
, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be [tex]3\times 0.100=0.300[/tex]
2. For 0.100 m [tex]LiNO_3[/tex]
[tex]LiNO_3\rightarrow Li^{+}+NO_3^{-}[/tex]
, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be [tex]2\times 0.100=0.200[/tex]
3. For 0.200 m [tex]C_2H_8O_3[/tex]
, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be [tex]1\times 0.200=0.200[/tex]
4. For 0.060 m [tex]Na_3PO_4[/tex]
[tex]Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}[/tex]
, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be [tex]4\times 0.060=0.24m[/tex]
Thus as concentration of solute is highest for [tex]K_2SO_4[/tex] , the elevation in boiling point is highest and thus has the highest boiling point.
