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Consider the hall reactions below for a chemical reaction
ZnZn2+ (aq) + 2e
Cu?" (aq) + 2e" - Cu(s)
What is the overall equation for this chemical reaction?
Zn(s) + Cu2+ (aq) -- Zn2+ (aq) + Cu(s)
Zn(s) + Cu2+ (aq) Cu* (ag)+ 2e"
Zn2+ (aq) + Cu(s) Cu(aq) + Zn(s)
Zn2+ (aq) + 2e" - Cu2(aq) + 2e

Respuesta :

quasarJose

Zn    +  Cu²⁺   →    Zn²⁺ +  Cu

Explanation:

The overall equation of this redox reaction is combination of the two half equations. The similar species on both sides are cancelled out leaving a net overall reaction:

           Zn → Zn²⁺  +  2e⁻      oxidation step

           Cu²⁺ + 2e⁻ → Cu        reduction step

Combining both equations:

Zn + Cu²⁺ + 2e⁻  → Zn²⁺  +  2e⁻  + Cu

since the common specie on both sides is  2e⁻, they cancel out to give an overall reaction:

                      Zn    +  Cu²⁺   →    Zn²⁺ +  Cu

learn more:

Redox reaction https://brainly.com/question/8727728

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