Answer:
20.94 m/s, 235.44 Pa
Explanation:
Acceleration due to gravity g = [tex] 9.81 m/s^2 [/tex]
height h = 0.024 m
From density of air = P/RT
= (98000)/(287 * 318.14) = [tex] 1.073 kg/m3 [/tex]
Using Bernoulli equation
[tex] (P/density*g) + (V^2/2g) + z = constant [/tex]
[tex] (P1/density*g) + (V1^2/2g) + z1 = (P2/density*g) + (V2^2/2g) + z2 [/tex]
Here z1 = z2 (since the outlets have the same differential height) and V2 = 0 (no velocity at the tip)
Solving and making V1 subject of the formula
[tex] V1 = \sqrt{(P2 - P1)/density of air} [/tex]
[tex] V1 = \sqrt{(2*density of water* g*h)/density of air} [/tex]
[tex] V1 = \sqrt{(2*1000*9.81*0.024/1.073} [/tex]
= 20.94 m/s
Change in pressure P2 - P1= density of water * g * height
= 1000*9.81*0.024
=235.44 Pa
