Answer:
The equation of the line is 4 x - y + 13 = 0.
Step-by-step explanation:
Here the given points are ( -4, -3) & ( -3, 1) -
Equation of a line whose points are given such that
( [tex]x_{1}, y_{1}[/tex] ) & ( [tex]x_{2}, y_{2}[/tex] )-
y - [tex]y_{1}[/tex] = [tex]\frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }[/tex] ( x - [tex]x_{1}[/tex] )
i.e. y - (-3) = [tex]\frac{ 1 - (-3)}{ (-3) - (-4)}[/tex] ( x- (-4))
y + 3 = [tex]\frac{1 + 3}{ -3 + 4}[/tex] ( x + 4 )
y + 3 = [tex]\frac{4}{1}[/tex] ( x + 4 )
y + 3= 4 ( x + 4)
y + 3 = 4 x + 16
4 x - y + 16 - 3 = 0
4 x - y + 13 = 0
Hence the equation of the required line whose passes trough the points ( -4, -3) & ( - 3, 1) is 4 x - y + 13=0 .
