Answer:
Therefore the area of parallelogram is 32 cm².
Step-by-step explanation:
Given:
[] ABCD is a Parallelogram .........Given
AB = 4 cm = Base
BC = 10 cm
CE = Height of Parallelogram
To Find:
area of parallelogram = ?
Solution:
In Right angle triangle BEC by Pythagoras theorem we have
[tex](\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}[/tex]
Substituting the values we get
[tex]10^{2}=6^{2} +CE^{2} \\\\CE^{2}=100-36=64\\ \\\therefore CE = 8\ cm\\[/tex]
Which is the Height of Parallelogram
Now, area of parallelogram given by
[tex]\textrm{Area of Parallelogram} = Base\times Height[/tex]
Substituting the values we get
[tex]\textrm{Area of Parallelogram} = 4\times 8=32[/tex]
[tex]\textrm{Area of Parallelogram} = 32\ cm^{2}[/tex]
Therefore the area of parallelogram is 32 cm².
