Answer:
50 rooms with kitchen facilities and 100 rooms without kitchen facilities
Step-by-step explanation:
Let the rooms without kitchen facilities be x and those with kitchen facilities be y
Form set of equations
Since the total rooms are 15, then the first equation is
x+y=150
Therefore, x=150-y
Considering the cost of rooms and what was collected, then
80x+100y=13000
Substituting x with 150-y then
80(150-y)+100y=13000
12000-80y+100y=13000
20y=1000
[tex]y=\frac {1000}{20}=50 rooms[/tex]
Therefore, x=150-y=150-50=100 rooms
Therefore, there are 50 rooms with kitchen facilities and 100 rooms without kitchen facilities