Answer:
option A : 64 g
Explanation:
Data Given:
no. of moles Cu(NO₃)₂ = 10 moles
mass of Cu = ?
Reaction Given:
3Cu +8HNO₃ ------→ 3Cu(NO₃)₂ + 2NO + 4H₂O
Solution:
First we have to calculate moles of Copper that react and moles of Cu(NO₃)₂ that produce in reaction :
For this look at reaction
3Cu +8HNO₃ ------→ 3Cu(NO₃)₂ + 2NO + 4H₂O
3 moles 3 moles
As 3 moles of Cu react to produce 3 moles of Cu(NO₃)₂
So,
1 mole of Cu (copper) will produce 1 mole of Cu(NO₃)₂
Now find the mass of 1 mole Cu (copper)
For this purpose formula used
mass in grams = no.of moles x molar mass
molar mass of Cu = 64 g/mol
Put values in above formula
mass in grams = 1 mol / 64 g/mol
mass in grams = 64 g
So 64 g of Cu is required to produce 1 mole of Cu(NO₃)₂
option A is correct.
