please help? algebra 1

Answer:
Question 1. What function describes the revenue of the tile factory in terms of the tiles sold?
Question 2. What is the flat-fee for delivery?
Explanation:
The equation y - 3,000 = 0.25(x - 10,000) is a linear function written in point-slope form.
To answer the first question, you can clear the dependent variable, y, in terms of the independent variable, x:
And that is the function that describes the revenue of the tile factory in terms of thenumber of tiles sold.
To answer the second question, the flat-fee delivery, you find the y-intercept of the linear function, i.e. the value of y when x = 0:
Hence the flat-fee delivery is $ 5,500.
Answer:
1) [tex]\text{Revenue}=0.25x^2+500x[/tex]
2) The flat-fee delivery is $500.
Step-by-step explanation:
Given : A tile factory earns by charging a flat fee for delivery and a sales price of $0.25 per tile.One customer paid a total of $3,000 for 10,000 tiles.The equation [tex]y-3,000=0.25(x-10,000)[/tex] models the revenue of the tile factory,where x is the number of tiles and y is the total cost to the customer.
To find :
1) Which function describes the revenue of the tile factory in terms of the tiles sold?
Total cost is
[tex]y-3,000=0.25(x-10,000)[/tex]
[tex]y=0.25x-10000\times 0.25+3000[/tex]
[tex]y=0.25x-2500+3000[/tex]
[tex]y=0.25x+500[/tex]
Revenue is defined as [tex]\text{Revenue}=\text{Quantity}\times \text{Cost}[/tex]
[tex]\text{Revenue}=x\times (0.25x+500)[/tex]
[tex]\text{Revenue}=0.25x^2+500x[/tex]
2) What is the flat-fee for delivery?
The flat-fee delivery is given by the y-intercept of the linear function, i.e. the value of y when x = 0
So, substitute x=0 in [tex]y=0.25x+500[/tex]
[tex]y=0.25(0)+500[/tex]
[tex]y=500[/tex]
Therefore, the flat-fee delivery is $500.